Name

XMLAGG — Produces a forest of elements from a collection of XML values

Synopsis

vector XMLAGG ( value_expression any );

Description

XMLAGG is aggregate function that produces a forest of XML elements from the given list of xml elements. It concatenates the values returned from one column of multiple rows, unlike XMLCONCAT , which concatenates the values returned from multiple columns in the same row.

The order of element in the result of XMLAGG is defined by the order of retrieval of the source data rows. It is important to remember that the order of rows in an SQL resultset defined only if there's an explicit ORDER BY clause. Hence if the order of elements in the resulting forest is important then XMLAGG should be applied to data that comes from inner SELECT statement that has an ORDER BY clause, not e.g. from a table reference.

Note that XMLAGG is actually declared as DB.DBA.XMLAGG but it is not important for plain use: for compatibility with other systems, any call of XMLAGG in any SQl statement is always replaced with the call of DB.DBA.XMLAGG , no matter which qualifier and user name are in use.

Parameters

value_expression

the result of one of the following functions XMLAGG , XMLCONCAT , XMLELEMENT , or XMLFOREST .

Return Types

The aggregate returns a vector that is a suitable input for functions XMLELEMENT , XMLCONCAT and xml_tree_doc .

Examples

Example24.494.XMLAGG() enclosed in XMLELEMENT()

The following example produces an 'Emp' element with attribute 'Title' and a list of all employees having the title 'Sales Representative' as element content.

select XMLELEMENT ('Emp', XMLATTRIBUTES ('Sales Representative' as "Title"),
       XMLAGG (XMLELEMENT ('Name', "FirstName", ' ', "LastName")))
  from "Demo"."demo"."Employees"
 where "Title" = 'Sales Representative';

callret
VARCHAR
_______________________________________________________________________________

<Emp Title="Sales Representative">
  <Name>Nancy Davolio</Name>
  <Name>Janet Leverling</Name>
  <Name>Margaret Peacock</Name>
  <Name>Michael Suyama</Name>
  <Name>Robert King</Name>
  <Name>Anne Dodsworth</Name>
</Emp>

1 Rows.

Example24.495.XMLAGG() that produces a sorted document

The result of the previous example contains an unsorted list of names. This is because data rows were retrieved from "Demo"."demo"."Employees" in primary key order, and this order has nothing common with fields "FirstName" and "LastName". To produce the sorted result, the query should contain ORDER BY in a subquery. These two variants will work identically if "FirstName" never contains whitespaces or nonprintable control characters, but the last one is formally more correct.

select XMLELEMENT ('Emp', XMLATTRIBUTES ('Sales Representative' as "Title"),
       XMLAGG (XMLELEMENT ('Name', "FirstName", ' ', "LastName")))
 from
    (select "FirstName", "LastName"
     from "Demo"."demo"."Employees"
     where "Title"= 'Sales Representative'
     order by 1, 2) as subq;

callret
VARCHAR
_______________________________________________________________________________

<Emp Title="Sales Representative">
  <Name>Anne Dodsworth</Name>
  <Name>Janet Leverling</Name>
  <Name>Margaret Peacock</Name>
  <Name>Michael Suyama</Name>
  <Name>Nancy Davolio</Name>
  <Name>Robert King</Name>
</Emp>

1 Rows.

select XMLELEMENT ('Emp', XMLATTRIBUTES ('Sales Representative' as "Title"),
       XMLAGG (XMLELEMENT ('Name', full_name)))
  from
    (select concat ("FirstName", ' ', "LastName") as full_name
     from "Demo"."demo"."Employees"
     where "Title"= 'Sales Representative'
     order by 1) as subq;

callret
VARCHAR
_______________________________________________________________________________

<Emp Title="Sales Representative">
  <Name>Anne Dodsworth</Name>
  <Name>Janet Leverling</Name>
  <Name>Margaret Peacock</Name>
  <Name>Michael Suyama</Name>
  <Name>Nancy Davolio</Name>
  <Name>Robert King</Name>
</Emp>

1 Rows.